0=30x^2+30x-180

Solution for 0=30x^2+30x-180 equation:

0=30x^2+30x-180

We move all terms to the left:

0-(30x^2+30x-180)=0

We add all the numbers together, and all the variables

-(30x^2+30x-180)=0

We get rid of parentheses

-30x^2-30x+180=0

a = -30; b = -30; c = +180;
Δ = b2-4ac
Δ = -302-4·(-30)·180
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-150}{2*-30}=\frac{-120}{-60}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+150}{2*-30}=\frac{180}{-60}
=-3
$